Re: unexpected behavior of ACCEPT

From: Anil Rodrigues <arodrix_at_weld.com>
Date: Thu, 5 May 2005 14:06:07 -0400

for what it's worth, in SwiftF

: try begin key? until pad 80 accept ;
try bc def ok
pad 10 dump
  46EB07 62 63 20 64 65 66 20 20 20 20 bc def =
 ok

That's by typing abc def, the 'a' disappears from the command line.

In Win32F I get the full 'abc def'.

Cheers! Anil

-----Original Message-----
From: Eglenn4511_at_aol.com [mailto:Eglenn4511_at_aol.com]
Sent: Wednesday, May 04, 2005 5:42 PM
To: sftalk_at_forth.com
Subject: [sftalk] Re: unexpected behavior of ACCEPT

=20
In a message dated 5/2/2005 2:37:03 P.M. Mountain Standard Time, =20
kbutterfield_at_lanl.gov writes:

: q1 1000 ms key? key emit ;

: q2 10000 ms key? if pad 10 accept pad swap dump then ;

q1 (immediatly type 1) returns 1
q2 (immediately type 1234) returns 234
q2 (wait 20 seconds type 1234) returns 1234

Where does the leading character go?

Ken B

Very interesting. Here is what I got.using win32forth
the 0 left on the stack came from somewhere ... I suspect I stopped =
typing =20
when key? accepted the first key=20
q2 1234
5652 31 32 33 34 1234 ok
=20
This was most interesting without waiting for the time delay. Nothing =20
appeared until the time delay was over. Then the hex representation of =
the numbers=20
appeared and the cursor sat behind the numbers. I pressed return and =
'1234'=20
appeared at the end of the line. I recognized the other numbers as the =
address=20
for pad. I 'typed' the contents of pad and as expected found 1234 as =
below.
5652 4 type 1234 ok
I didn't do the third part because I knew it would be accepted as a =
numeric=20
input. It doesn't go to pad because 'if' sees false.
=20
=20
Charlie

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Received on Thu May 05 2005 - 11:08:48 PDT


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